Having alot of trouble with projectile motion prob

AI Thread Summary
A football is kicked at a speed of 10.0 m/s at a 39.0° angle, and the goal is to determine when it hits the ground. The initial vertical velocity (Voy) is calculated as 10sin(39°), and the equation of motion is applied to find the time of flight. The correct setup involves using the vertical motion equation, with the initial height (Yo) set to zero since the kick occurs at ground level. The discussion highlights the importance of ensuring the calculator is set to degrees, not radians, for accurate calculations. Ultimately, the flight time can be derived by solving the motion equation for time when the vertical displacement is zero.
justinbaker
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A football is kicked at ground level with a speed of 10.0 m/s at an angle of 39.0° to the horizontal. How much later does it hit the ground?

i found the Voy to be 10sin(39), then i used Y=Yo + Vot + .5at^2 and i solved for t. I found t to be 1.97s

but for some reason it is showing that i am wrong on my online hw, please help
 
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Your calculator is working in radians, but you're working in degrees.
 
thanks man, i feel like an idiot, your awsome
 
how did you set it up?

Y=Yo + Vot + .5at^2
0 = Yo + (10)t + .5(-9.8)t^2 <--a is -9.8 right? cause it's going down

what is Yo?


"i found the Voy to be 10sin(39)"

isnt that the velocity? so you can't plug that in for Yo.


how did you get your answer? i have the same type of problem
 
A football is kicked at ground level with a speed of 10.0 m/s at an angle of 39.0° to the horizontal. How much later does it hit the ground?

Info:
V_{o} = 10 m/s
\theta_{o} = 39^o
Y_{o} = 0 The Football was at ground level
T_{f} = ? <- Flight time

Remember we can work this problem with V_{o} components
V_{yo} = V_{o}\sin(\theta_{o})
V_{xo} = V_{o}\cos(\theta_{o})

We can use the equation you used.
Y = 0 when it hits the ground.
0= Y_{o} + V_{yo}t_{f} - \frac{1}{2}gt^2_{f}
0= Y_{o} + V_{o}\sin(\theta_{o})t_{f} - \frac{1}{2}gt^2_{f}
0 = V_{o}\sin(\theta_{o})t_{f} - \frac{1}{2}gt^2_{f}

Simply solve for Flight Time.
 
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