Heat conduction through a layers of different materials

Click For Summary

Homework Help Overview

The discussion revolves around heat conduction through layers of different materials, specifically focusing on the equations related to heat transfer and the role of area in these equations.

Discussion Character

  • Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to understand the placement of area in the equations for heat conduction and questions the reasoning behind its position in the numerator versus the denominator.

Discussion Status

Some participants provide insights on manipulating the equations to clarify the role of area, suggesting that if the areas are equal, one can adjust the equations accordingly. However, there is no explicit consensus on the implications of differing material properties in this context.

Contextual Notes

The original poster expresses confusion regarding the textbook's presentation of the equations and the assumptions about the areas and thermal conductivities involved in the problem.

curiosity colour
Messages
21
Reaction score
0

Homework Statement


Question C(ii)
23513252_1863108113702914_1119620298_n.jpg

23476270_1863108110369581_2138216208_n.jpg

Homework Equations


dQ/dt =-kA(dθ/dx)
dQ/dt = (θ12)/ ((lx/kxAx)+ (ly/kyAy))

The Attempt at a Solution


So the first time I tried at this question, I was using the second equation provided above,but when I check the answer, they put the area on the numerator. which left me wonder, how did they make it on top, I've check my textbook but none of it give any clues. If area is on the numerator with θ, I think k should be too isn't it?
 

Attachments

  • 23513252_1863108113702914_1119620298_n.jpg
    23513252_1863108113702914_1119620298_n.jpg
    26.6 KB · Views: 797
  • 23476270_1863108110369581_2138216208_n.jpg
    23476270_1863108110369581_2138216208_n.jpg
    23.5 KB · Views: 800
Physics news on Phys.org
If Ax = Ay = A, you can multiply numerator and denominator by A, so A will appear in the numerator and not the denominator. You can do the same with k if kx = ky, but that is not the case in this problem.
 
I’ve moved this to the precalculus math forum where they can help you learn algebra.
 
mjc123 said:
If Ax = Ay = A, you can multiply numerator and denominator by A, so A will appear in the numerator and not the denominator. You can do the same with k if kx = ky, but that is not the case in this problem.
I see, thanks for your answer
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
2K
Replies
2
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 13 ·
Replies
13
Views
3K
Replies
10
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 10 ·
Replies
10
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K