Heat problem, determine mass of ice cube?

AI Thread Summary
The discussion revolves around calculating the mass of an ice cube based on heat transfer principles. The initial calculation yielded 12.9 grams, while the correct answer is 11.9 grams. The mistake identified involves the application of the heat of fusion constant and the misunderstanding of temperature changes during the phase transition. It is clarified that separate calculations for the ice and the resulting water are necessary due to differing specific heat capacities. The importance of accurately accounting for phase changes in thermal calculations is emphasized.
gibson101
Messages
47
Reaction score
0
My answer is 12.9 grams, and the correct answer is supposed to be 11.9 grams. I cannot figure out why? Note. the answer i got is 12.9, and not 11.06. I know for this situation, the heat absorbed by the ice equals the heat lost by the water and aluminum, and since there is a phase change from a solid to liquid then i need the heat of fusion constant for solid water, which in kcal/kg which is 79.7. Now I am thinking that this is where my mistake is, because temperature remains constant during a phase change. Therefore, I cannot put 16-(-8.7)? I have to write it out into two separate m*c*deltaT's?
 

Attachments

  • Screen shot 2011-06-18 at 5.53.02 PM.JPEG
    Screen shot 2011-06-18 at 5.53.02 PM.JPEG
    11.5 KB · Views: 591
  • 11.jpg
    11.jpg
    16.4 KB · Views: 511
Last edited:
Physics news on Phys.org
Yes, you need two separate m*c*deltaT-s for the ice, as c of ice is different from that of water it becomes after melting.

ehild
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top