- #1
rvaafrica
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1. You have a heat pump which has a coefficient of performance (C.O.P.) that is 17% of the maximum achievable. You want to heat your house to 20◦C. At what outside temperature does the heat pump become not useful?
2. C.O.P. = 1/(T1/T0 - 1)
T1= Temperature of the outside
T0 = Temperature of the house
3. Hi. Basically I am NOT looking for someone to give me an answer. I would just like some help on how to approach this problem. I know how to solve for T1 if they give the maximum C.O.P but I am stuck on how to complete this problem since the max. C.O.P is not given. Any help would be greatly appreciated.
2. C.O.P. = 1/(T1/T0 - 1)
T1= Temperature of the outside
T0 = Temperature of the house
3. Hi. Basically I am NOT looking for someone to give me an answer. I would just like some help on how to approach this problem. I know how to solve for T1 if they give the maximum C.O.P but I am stuck on how to complete this problem since the max. C.O.P is not given. Any help would be greatly appreciated.