Heat removed from a gas in a cylinder

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Homework Statement



A piston (with an area of 3.14 x 10^-2 m/s^2) is pushing down on a vertical cylinder (with a pressure of 1.01 x 10^5 Pa) which contains an monotomic ideal gas. 2093 J of heat is removed from the gas.
Ignoring the mass of the piston or friction, find how far the piston has dropped.

Homework Equations



I believe that I will have to use Uf-Ui = Q - w,

but I have already figured that the process would have to be isobaric, whoch is goverend by the equation W = P (Vf-Vi), which can be suited to our needs by using distance multiplied by area for the volume, so
W = P A(change in d)

Im wondering if I am going to have to use formulas related to specific heat capacities, but Im not quite sure. Any ideas?
 

Answers and Replies

  • #2
Andrew Mason
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A piston (with an area of 3.14 x 10^-2 m/s^2) is pushing down on a vertical cylinder (with a pressure of 1.01 x 10^5 Pa) which contains an monotomic ideal gas. 2093 J of heat is removed from the gas.
Ignoring the mass of the piston or friction, find how far the piston has dropped.

Homework Equations



I believe that I will have to use Uf-Ui = Q - w,

but I have already figured that the process would have to be isobaric, whoch is goverend by the equation W = P (Vf-Vi), which can be suited to our needs by using distance multiplied by area for the volume, so
W = P A(change in d)

Im wondering if I am going to have to use formulas related to specific heat capacities, but Im not quite sure. Any ideas?
(hint: when you see "monatomic" or "diatomic" mentioned in a problem there is likely going to be an issue involving heat capacity). You don't have to calculate the work done here.

This is an isobaric process since the force on the cylinder does not change. So how is T related to V?

If you remove 2093 J. how much does the temperature change? Work out final V from that.

AM
 

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