Heat transmitted in convection from a pipe

AI Thread Summary
A vertical steam pipe with a diameter of 7.5 cm and a height of 4 m maintains an outer surface temperature of 950°C, while the surrounding air is at 20°C. The calculated heat delivered to the air by natural convection over one hour is approximately 848,469 Cal/hr, but the expected answer is 454,000 Cal/hr. There are concerns about the calculation method, particularly regarding the use of volume instead of cross-sectional area. Additionally, another user is seeking help with determining heat loss in steam pipes exposed to wind, facing challenges with high Reynolds numbers that exceed the valid range for standard Nusselt number equations. The discussion emphasizes the need for accurate heat transfer coefficient calculations in both natural and forced convection scenarios.
Karol
Messages
1,380
Reaction score
22

Homework Statement


A vertical steam pipe of outside diameter 7.5 cm and height 4 m has its outer surface at the constant temperature of 950C. The surrounding air is at atmospheric pressure and at 200C.
How much heat is delivered to the air by natural convection in 1 hr?

Homework Equations


\mbox{The heat convection current H: }H=hA\,\Delta t
\mbox{Coefficient of naural convection in air at atmospheric pressure for a vertical pipe (diameter D): }h=1.00\times10^{-4\left(\frac{\Delta t}{D}\right)^{1/4}}

The Attempt at a Solution


h=1.00\times10^{-4\left(\frac{75}{7.5}\right)^{1/4}=0.00018
H=0.00018\cdot\frac{\pi\cdot 7.5^2}{4}400\cdot 75=235.7\left[Cal/Sec\right]=848,469\left[Cal/hr\right]
The answer, according to the book, should be 454,000.
If this isn't the place for this subject, please guide me to another sight that deals with those kind of problems.
 
Physics news on Phys.org
I see you have '400' in your final line. I don't think that belongs there, else you are essentially multiplying by volume and not cross-sectional area 'A'.
 
I have a similar question. I'm trying to determine the heat loss in our steam pipes both outside exposed to the wind(forced convection) and inside our plant(free convection). I'm having some trouble in determining the heat transfer coefficient, h for both situations. When I calculate the Reynold's number for the wind blowing on the pipes, its so large that I can't use any of the normal equations to find the Nusselt number. The equations I'm using are
Nu = hl/k where h is heat transfer coefficient, l is a characteristic length (I'm using the diameter of the pipe and insulation), and k is the thermal conductivity of the insulation.
and
Nu = .023Re^.8 * Pr^.3 this range is valid for approx 100< Re < 50,000
My Re is 300,000+

Suggestions?
Thanks
 
cmpersson said:
I have a similar question. I'm trying to determine the heat loss in our steam pipes both outside exposed to the wind(forced convection) and inside our plant(free convection). I'm having some trouble in determining the heat transfer coefficient, h for both situations. When I calculate the Reynold's number for the wind blowing on the pipes, its so large that I can't use any of the normal equations to find the Nusselt number. The equations I'm using are
Nu = hl/k where h is heat transfer coefficient, l is a characteristic length (I'm using the diameter of the pipe and insulation), and k is the thermal conductivity of the insulation.
and
Nu = .023Re^.8 * Pr^.3 this range is valid for approx 100< Re < 50,000
My Re is 300,000+

Suggestions?
Thanks

you should start your own thread, but your Re is outside the range for that equation, thus it cannot be used for your problem.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top