Heating an Ideal Gas: Why Burning Fuel is Equivalent to Reversible Heating

Katie1990
Messages
6
Reaction score
0

Homework Statement



I'm struggling to explain why for an ideal gas at constant pressure heating by burning fuel is equivalent to reversible heating. I know that all forms of work on a ideal gas are eqivalent but don't know why.

Homework Equations





The Attempt at a Solution

 
Physics news on Phys.org
I wouldn't call the two cases equivalent. In what ways of equivalency do you mean?
 
The question asks me to explain why burning a fuel that is clearly not reversible is the same as if heat was supplied reversibly.
 
To solve this, I first used the units to work out that a= m* a/m, i.e. t=z/λ. This would allow you to determine the time duration within an interval section by section and then add this to the previous ones to obtain the age of the respective layer. However, this would require a constant thickness per year for each interval. However, since this is most likely not the case, my next consideration was that the age must be the integral of a 1/λ(z) function, which I cannot model.
Back
Top