Heating Mineral Water to 60°C Using Plain Water at 100°C

[dogcat]

Homework Statement

How can you heat 1 \,\mathrm{kg} mineral water which is at a temperature of 0 \,{}^\circ \mathrm{C} to at least 60 \,{}^\circ \mathrm{C} with using 1 \,\mathrm{kg} plain water at a temperature of 100 \,{}^\circ \mathrm{C}?

Homework Equations

\Delta Q = mc\Delta T

The Attempt at a Solution

\underbrace{(1000 g)(4.18~J/g~C)(60~C)}_{\text{heat gained}} = \underbrace{m(4.18~J/g~C)(100~C - 60~C)}_{\text{heat lost}}
But then m>1000 g. So I really don't know how to do it. There should be a nasty trick in it.

 

[Kilopilo]

Check your cp's. They should be different given the temperature difference and though subtle, material difference.

 

[dogcat]

Thanks but don't think that there are so much difference between them. Any other ideas?