How to Calculate the Molar Heat of Vaporization of Dichloromethane?

AI Thread Summary
To calculate the molar heat of vaporization of dichloromethane (CH2Cl2), the vapor pressure at 0 degrees Celsius is given as 134 mmHg, with a normal boiling point of 40.0 degrees Celsius. The equation used involves the natural logarithm of the pressure ratio and the heat of vaporization, but the user struggles with determining the unknown pressure variable, P_2. The concept of boiling is clarified as the rapid vaporization of a liquid at its boiling point, where vapor pressure equals environmental pressure. The user ultimately finds the solution to their problem. Understanding the relationship between vapor pressure and temperature is crucial for this calculation.
Kudo Shinichi
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HELP!A question on vapour pressure

Homework Statement


The vapor pressure of dichloromethane, CH2Cl2, at 0 degree Celsius is 134 mmHg. The normal boiling point of dichloromethane is 40.0 degree Celsius. Calculate its molar heat of vaporization.


Homework Equations





The Attempt at a Solution



ln(P_2/134)=(Change of H_vapour/8.314)(1/(0+273)-1/(40+273))
I still have two unknown variables...I should find change H_vapour for this question, but I don't know how to figure out P_2

Thank you for helping me.
 
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What does boliling mean?
 


Borek said:
What does boiling mean?

Boiling (also called ebullition), a type of phase transition, is the rapid vaporization of a liquid, which typically occurs when a liquid is heated to its boiling point, the temperature at which the vapor pressure of the liquid is equal to the pressure exerted on the liquid by the surrounding environmental pressure
Source: wikipedia
 


Answer to your problem is directly addressed in the quote.
 


Thanks. I have got the answer.
 
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