Help Me Calculate How high SuperMan can Jump

  • Thread starter Thread starter theoblivin8r
  • Start date Start date
  • Tags Tags
    Jump Superman
AI Thread Summary
To calculate how high Superman can jump, the initial velocities in the x and y directions are established as 1.26 m/s and 180.99 m/s, respectively. The key to solving for the maximum height is recognizing that at the peak of his jump, his final vertical velocity (Vy) is zero. The relevant equations of motion can be rearranged to find the height, but the challenge lies in determining time or another variable. The discussion emphasizes using projectile motion principles rather than energy methods to arrive at the solution. Understanding that Vy equals zero at the highest point is crucial for solving the problem effectively.
theoblivin8r
Messages
9
Reaction score
0

Homework Statement


This is a semester review. I am having trouble starting the second part of this question. It is well-know fact that Superman is "faster than a speeding bullet, more powerful than a locomotive, and able to leap tall buildings in a single bound." Assume his mass is 100kg.

The first part we are given his initial velocity as 181 m/s. That is one meter faster than a characteristic bullet. His jump takes off at a 86.9 degree angle. What are his initial velocities in the x and y direction. No trouble here.

V(xinitial)=1.26 m/s
V(yinitial)=180.99 m/s

The second part asks how tall of a building can he leap using the above data.

Homework Equations


Y=Yinitial)+V(yinitial)(time)+1/2Ay*(time^2)

V(yfinal)^2=V(yinitial)^2+Ay(X-Xinital)

V(yfinal)=V(yinitial)+Ay*Time

The Attempt at a Solution


I have his initial velocities in the x and y direction. I am confused on how to solve for a final velocity without knowing time or the final velocity in the y direction. I am thinking that since I have two unknowns I might have to rearrange and equation and substitute it into another one to solve for one unknown. Any help is greatly appreciated!
 
Physics news on Phys.org
Here's a hint: when superman is at the highest point in his jump, his vertical velocity (let's call this his "y velocity") is zero. (He starts with a positive y velocity, and if his y velocity were positive at the peak of his jump, he'd keep going up--so it wouldn't be the peak of his jump). So you can use V_y=0 for your final velocity. The horizontal or x velocity doesn't really matter in this problem, since it stays constant throughout. Honestly, including a small x velocity in this problem is probably just meant to confuse you.

However, I think there's an easier way to solve this problem. Use kinetic and potential energies.
 
Thanks for the hint. I had missed that key information. I have to solve this using projectile motion and not energy so thanks anyway. I'll post questions if I have anymore.
 
When the super man reaches the highest point of the building, his Vy(final) can be taken as zero.
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Back
Top