Help me find the radius of convergence?

madcattle
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Homework Statement


Ʃn!(x-1)n
I need to find the radius of convergence for this summation from n=0 to n=∞


The Attempt at a Solution


I started off with the ratio test:

(n!(n+1)(x-1)(x-1)n)/(n!(x-1)n) = (n+1)(x-1)

(x-1)lim(n+1)...Now at this point it looks to me like the series does not actually converge, but my book is telling me that it does. Am I looking at something the wrong way? Not actually understanding the problem?
 
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It looks like it converges only at x = 1.
 
Last edited:
Usually you do the ratio test on the part of the sum that doesn't have the factor with x, so in this case with just n!. Simplifying that gets you L = limn→∞(n+1) = ∞ and the radius of convergence is r = 1/L = 0.

The only x value where it converges is x=1.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...

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