Help me to understand basic circuit analysis solution

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Discussion Overview

The discussion revolves around understanding basic circuit analysis, specifically the calculation of effective resistance in a circuit with resistors in parallel and series. Participants explore different approaches to solving the problem presented in a homework assignment.

Discussion Character

  • Homework-related
  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant questions the reasoning behind using the combination of (12||6) and then adding 2k(ohms), expressing confusion over why (12||8) was not used instead.
  • Another participant suggests that redrawing the circuit can help simplify the analysis and recommends starting with the resistances farthest from the source.
  • A later reply offers a step-by-step method for calculating the effective resistance, proposing an alternative approach that involves solving (2k//6k) first, followed by (4k//12).

Areas of Agreement / Disagreement

Participants do not reach a consensus on the best method for calculating effective resistance, as different approaches are presented and debated without resolution.

Contextual Notes

Some participants express uncertainty about the order of operations in calculating effective resistance, indicating that there may be multiple valid methods depending on the circuit configuration.

Who May Find This Useful

Students learning circuit analysis, individuals seeking clarification on resistor combinations, and those interested in different problem-solving strategies in electrical engineering.

General_Sax
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Homework Statement


given in uploads.

Homework Equations


The Attempt at a Solution



I just don't understand why they went [(12||6) + 2]

I tried doing (12||8) and I ended up getting the wrong answer.

Why do you have to add the 2k(ohms) to the effective resistance of the 12||6 k(ohms)?

Why couldn't one use 12||8 ?

Another question: Is there any paticular order to calculating the effective resistance?

ie, does one have to work outside -> inside or something similar?

Please and thank you!
 

Attachments

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Before beginning to work the problem it helps to redraw the circuit to simplify it, at least in your mind, as in the attachment.

It usually is best to start with the resistances farthest from the source and work back towards the source.

So in the attached circuit do you see why first the parallel combination of the 12k and 6k are calculated and then 2k is added?
 

Attachments

That makes much more sense. Thanks for your time!
 
there is a simpler method. i.e;
solve the:
step 1: 2k//6k
step 2: 4k//12
step 3: draw the circuit equivalent whereas u will have the rest in parallel
step 4: u will get exactly 2k
 

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