Help Needed: Solve Circuit Analysis Problem

AI Thread Summary
An electrical engineering student seeks help with a circuit analysis problem involving voltage differences and current flow. The problem requires determining the voltage difference between two points and calculating potential drops across components using Kirchhoff's Voltage Law (KVL). The student questions whether certain components, like a 5V battery and a 10-ohm resistor, can be disregarded during the KVL walk. Responses clarify that the 5V battery's voltage remains constant and that the potential drop across a resistor is zero if no current flows. The discussion emphasizes understanding circuit components' roles in analysis.
Cetullah
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Hello dear Physics Forums community, I need your help! I m an electrical engineering student in second class, and I m stuck with a different kind of problem (probably different to me only, lawl) in the Circuit Analysis.

I believe this problem will be a stepping stone for the other problems I can't solve yet.

Homework Statement



In the attachment.

Homework Equations



Guess they are the Voltage law and Current Law.

The Attempt at a Solution



I m stuck, can't do a thing, will appreciate the attempts to guide me to solution.

Thank you!

Edit, Lol, the problem asks the voltage difference between point a,(the corner on left-top) and point b(the left-bottom corner of the loop in right)
 

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  • kirchoff.png
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Indicate on your diagram where currents are flowing. Then determine the potential drops across all the components. Do a "KVL walk" from point a to point b.

Hint: A continuous current requires a complete circuit.
 
Hmm, so I guess there's no current flowing through the line in the middle?
 
Cetullah said:
Hmm, so I guess there's no current flowing through the line in the middle?

That happens to be a good guess.
 
Nice! And can I simply discard the 5v battery and the 10 ohm resistor when I m doing the KVL walk?
 
Cetullah said:
Nice! And can I simply discard the 5v battery and the 10 ohm resistor when I m doing the KVL walk?

Nope. The 5V voltage remains 5V no matter what; it's an ideal supply and cannot change. What's the potential drop across the resistor if the current is zero?
 
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