Help Needed: Solving y = A sin({2*10^6 ({\pi / 3 -\pi t }) + \phi })

  • Thread starter Thread starter MichaelTam
  • Start date Start date
  • Tags Tags
    Phi Waves
AI Thread Summary
The discussion revolves around solving the equation y = A sin(2*10^6 (π/3 - πt) + φ) and determining the time variable t. The formula for signal strength s(x, t) is mentioned, but the focus is on finding the time for the signal to travel a distance of 1.0 x 10^6 m. To calculate this time, the speed of the wave (v) must be determined from the given data. The key question is whether the speed can be derived from the provided information.
MichaelTam
Messages
93
Reaction score
6
Homework Statement
Exercise
Relevant Equations
##v = f \lambda , s({x,t}) = A sin({k x - \omega t + \phi}) ##, other statements are provided in the picture.
I know so ## y = A sin({2*10^6 ({\pi / 3 -\pi t }) + \phi }) ##
There still some unknown I cannot find, can anyone give me some hint please?
 

Attachments

  • F6104606-1371-4F46-A8C2-185EE2372EAB.png
    F6104606-1371-4F46-A8C2-185EE2372EAB.png
    21.7 KB · Views: 132
Last edited:
Physics news on Phys.org
But how can I find t?## \lambda = 3 ## because ## k = 2 \pi/3 = 2 \pi/\lambda##
 
Last edited:
MichaelTam said:
But how can I find t?## \lambda = 3 ## because ## k = 2 \pi/3 = 2 \pi/\lambda##
The formula ##s(x, t) = A sin(k \cdot x - \omega \cdot t + \phi)## gives you the signal strength (##s##) at a particular position (##x##) and time (##t##). If you wanted the time at which ##s## had some particular value, you would use the formula. But that is not what the question is about.

You simply want the time for the signal to travel a distance of ##1.0 \times10^6 ## m. So you use:

##time = \frac {distance}{speed}##

You know the distance is ##1.0 \times 10^6 ## m. So the real question is can you find the speed (##v##) of the wave from the data supplied?

Edit: minor changes to improve wording.
 
Last edited:
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Back
Top