Help on 2 Physics Problems: Proton-Helium Collision & Tennis Ball Impulse

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A proton colliding elastically with a helium nucleus requires the application of conservation of momentum and energy to determine the final velocities of both particles. The initial momentum of the proton must equal the combined momentum after the collision, while kinetic energy must also be conserved. For the tennis ball problem, the impulse imparted to the wall is calculated by focusing on the change in momentum perpendicular to the wall, as parallel momentum does not affect the impulse. The angle of incidence and rebound at 45 degrees is crucial for determining the impulse's magnitude and direction. Understanding these principles is essential for solving both physics problems effectively.
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Hey all, I am in need of desperate help, any comments would be a huge help! thanks.

A proton moving at 3x10^5 m/s [E], strikes a helium nucleus at rest. If the collision is perfectly elastic, find the velocities of each after the collision. Assume the collision is 1 dimensional.

A tennis ball of mass m and speed v strikes a wall at 45degree angle and rebounds with the same speed at 45degrees. What is the impulse given the wall? [Hint: Magnitude and Direction are needed]

Thanks for any help,
Jeremy
 
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For 1, try conservation of momentum and conservation of energy.

So mHvH is the momentum before, and must equal the momentum after, and

1/2 mHv2H is the KE before and must equal the KE of both particles after.

Use the relationship of momentum to partition the KE. The problem stated represents a head-on collision with full recoil.

For 2, the change in momentum normal to the plane of the wall contributes to the impulse. The momentum parallel to the wall does not contribute to the impulse.
 
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