Calculating Thrust and Lift Forces for a Jet Fighter Taking Off at 27 Degrees

  • Thread starter Anisotropic Galaxy
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In summary, to find the thrust T of a jet fighter taking off at an angle of 27.0 degrees with the horizontal and accelerating at 2.62 m/s*s, the mass of the plane (79,300 N divided by g) must be multiplied by the acceleration. The lift force L exerted by the air perpendicular to the wings can be found by using the equation L = 89,000 N - mgsin27. Other equations that may be used include T = m(a_x) + mgsin27 and L = mgcos27 and T = m(a_x) + mgsin27.
  • #1
Anisotropic Galaxy
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A jet fighter takes off at an angle of 27.0 degrees w/ the horizontal, accelerating at 2.62 m/s*s. The plane weighs 79,300 N. I need to find the thrust T of the engine on the plane and the lift force L exerted by the air perpendicular to the wings.

Thanks

My reasoning so far...

79,3000 N / g = 8084 kg.

F = ma = 2.62 m/s^2 * 8092 kg -> 21179 N.

So I'm thinking that be the thrust.

As for the lift force L though, I don't know. Could I use sin or cosine?
 
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  • #2
Anisotropic Galaxy said:
A jet fighter takes off at an angle of 27.0 degrees w/ the horizontal, accelerating at 2.62 m/s*s. The plane weighs 79,300 N. I need to find the thrust T of the engine on the plane and the lift force L exerted by the air perpendicular to the wings.

Thanks

My reasoning so far...

79,3000 N / g = 8084 kg.

This is the mass of the airplane. You'll need it.

Here's a list of all the forces that act upon the plane:
- gravity
- lift of the wings
- thrust of the engines

That's 3 forces (try to find in what direction they are applied ; make a drawing of the forces). Find the total force.

Now, the airplane is not in equilibrium. It is accelerating. So what should you do with the 3 forces ? What equation should you use ? (hint: Newton...)

F = ma = 2.62 m/s^2 * 8092 kg -> 21179 N.

That should be the total force, yes...

So I'm thinking that be the thrust.

As for the lift force L though, I don't know. Could I use sin or cosine?

No, it is not the thrust. It is the total force (of which thrust is only a part)...

Leave you here...
 
  • #3
Is the thrust simply cos(27.0)*21179 N then?

So...the force of the lift is 89,000 N, right? a_y = 2.62 m/s^2*sin27.0 = (Lift - mg)/m so then by substituting things, Lift = 89,000 N.
 
  • #4
But someone else got a different answer than me, so I'm probably wrong here...
 
  • #5
Does


Should i switch the axis around, and then the Force of the thrust = (2.62cos27-gsin27)m and L equal to (2.62sin27+gcos27)m?

sound right...?
 
  • #6
or.. maybe not?

L = mgcos27 and T = m(a_x) + mgsin27?
 

1. What is 3D motion?

3D motion refers to the movement of objects in three-dimensional space. This includes the motion of objects along the x, y, and z axes, as well as any rotation or changes in orientation.

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The main difference between 2D and 3D motion is the number of axes involved. 2D motion occurs only along the x and y axes, while 3D motion includes movement along the z axis as well. Additionally, 3D motion can involve rotation and changes in orientation, while 2D motion is limited to linear movement.

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