How much mass can a brass spring hold without becoming permanently bent?

AI Thread Summary
The discussion focuses on determining how far a mass attached to a brass spring drops before the spring stops it and begins to bounce back, using conservation of energy principles. Participants emphasize the importance of establishing a baseline for potential energy and suggest using the spring's rest position for calculations. Key equations involve the kinetic energy of the mass, gravitational energy, and the energy absorbed by the spring. Additionally, it is noted that if the spring stretches more than 50 cm, it will become permanently bent, prompting a calculation for the maximum safe mass to use in the experiment. The conversation highlights the need for precise calculations to avoid damaging the spring.
psruler
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Hi, i need help on this problem:

A brass spring (with spring constant k) with no mass on it hangs vertically from fixed support bar, at rest. You attach a mass m to the free end and release it; how far does the mass drop before the spring brings it to a (brief) stop and it starts to bounce back: Use conservation of energy, and show your work. Solve for your answer in terms of k, m, and g. Ignore mass of the spring itself.

2) Your spring stretches more than 50 cm from its rest position, it will become permanently bent out of shape. What is the largest mass ( to 2 significant figures) that you would dare to use for your dropping experiment in part (a)? Assume the same value for k.
 
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I'm going to have to venture a guess at this, since you haven't posted any of your work.

You need to establish a baseline for the potential energy. It doesn't matter where it is because only the change in potential energy is what's important, but you need to arbitrarily establish one never-the-less. I suggest using either the rest position of the spring or the (as yet unknown) lowest position of the mass.

From there, why don't you write the conservation of energy equation and see what you get?

cookiemonster
 
Observe that the kinetic energy of the mass at a distance x from rest equals the energy transferred by gravity ( mgx ) minus the energy absorbed by the spring ( \frac{1}{2}kx^2). Use this info to solve for x when the kinetic energy is zero.

You can verify that result by setting up an equation for the acceleration ( g-(\frac{k}{m})x ) and integrating it to find its velocity and setting that to zero.
 
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Thanks palpatine!
 
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