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**1. Homework Statement**

[tex]\int[/tex][tex]\frac{cosxdx}{\sqrt{1+cosx}}[/tex]

**2. Homework Equations**

n/a

**3. The Attempt at a Solution**

Well I tried:

u=cosx

x=arccosx

dx=[tex]\frac{-du}{\sqrt{1-u^2}}[/tex]

Plugging them back into the integral gives me:

-[tex]\int[/tex][tex]\frac{udu}{\sqrt{1-u^2}\sqrt{1+u}}[/tex]

I don't know where to go from there.

I've also tried:

[tex]\int[/tex][tex]\frac{cosx\sqrt{1-cosx}dx}{sin^2x}[/tex]

or:

[tex]\int[/tex][tex]\sqrt{\frac{cos^2x}{1+cosx}}dx[/tex]

But I don't know where to go from any of the above attempts. Any help would be greatly appreciated.

**1. Homework Statement**

**2. Homework Equations**

**3. The Attempt at a Solution**