Help on problem for physics point charges

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Two point charges, +5μC and -6μC, are placed 0.02m apart, creating an attractive force due to their opposite charges. To calculate the force between them, Coulomb's Law can be applied, which indicates that the force magnitude is proportional to the product of the charges and inversely proportional to the square of the distance between them. The negative charge will exert a greater force on the positive charge, but both charges experience equal magnitude forces according to Newton's Third Law. The interaction is an attracting force due to the opposite signs of the charges. Understanding these principles is essential for solving the problem effectively.
Captain cook
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Two point charges, one measuring +5μC and the other -6μC are placed .02m apart. What is the force between the two charges? Which point charge exerts the greater force on the other? Is it an attracting or repelling force? 1μC= 1x 10 to the negative sixthC
 
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Captain cook said:
Two point charges, one measuring +5μC and the other -6μC are placed .02m apart. What is the force between the two charges? Which point charge exerts the greater force on the other? Is it an attracting or repelling force? 1μC= 1x 10 to the negative sixthC
Hello Captain cook. Welcome to PF !

What have you tried?

Where are you stuck?


According to the rules of this Forum, you need to show what you have tried, before we can help you.
 
Physics homework

I just don't understand the question so therefore i have tried very little.
 
Captain cook said:
I just don't understand the question so therefore i have tried very little.
Do you know Newton's Laws of Motion? --- In particular, Newton' Third Law.

You can answer one of the questions using this.
 

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