Help on tis quadratic functions question

AI Thread Summary
The discussion revolves around solving a quadratic function related to the speed of a particle, expressed as v = 10t - t². The goal is to demonstrate that the particle maintains a speed of 5 m/s or greater for exactly 4√5 seconds. The initial attempt involved setting up the inequality 10t - t² > 5, leading to the quadratic equation t² - 10t + 5 < 0. The solution reveals that the relevant time interval is between the two roots, calculated as 4√5 seconds, confirming the problem's requirements. The conversation emphasizes the importance of recognizing the solution without getting lost in decimal approximations.
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[SOLVED] Help on tis quadratic functions question

Homework Statement


The speed v m/s of a particle traveling from A to B at time t s after leaving A, is given by v =10t-t². the particle starts from rest at A and comes to rest at B. Show that the particle has a speed of 5m/s or greater for exactly 4\sqrt{5} s



Homework Equations


NOne


The Attempt at a Solution



10t-t²>5
t²-10t+5 <0
0.52 < t < 9.47
then i don't know how to do already.
Can someone start me off and guide me along?
 
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consider using the quadratic formula
 
Sigh. You have already solved the problem, but because you are so infatuated with decimal approximations, you don't see the answer even when it stares you in the eye.

On your second line, we factorize the quadratic, with the two zeroes:
X=\frac{-(-10)\pm\sqrt{(-10)^{2}-4*1*5}}{2*1}=\frac{10\pm\sqrt{80}}{2}=\frac{10\pm\sqrt{16*5}}{2}=5\pm{2}\sqrt{5}

You have found that the relevant region lies between these 2 zeroes, and we may then calculate the distance between them:
(5+2\sqrt{5})-(5-2\sqrt{5})=4\sqrt{5}
as was to be shown.
 
I picked up this problem from the Schaum's series book titled "College Mathematics" by Ayres/Schmidt. It is a solved problem in the book. But what surprised me was that the solution to this problem was given in one line without any explanation. I could, therefore, not understand how the given one-line solution was reached. The one-line solution in the book says: The equation is ##x \cos{\omega} +y \sin{\omega} - 5 = 0##, ##\omega## being the parameter. From my side, the only thing I could...
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