Help Period of oscillation of the mass

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The discussion centers on calculating the period of oscillation for a mass-spring system. The mass is displaced 0.16 m from its equilibrium position and at t = 0.50 s, it is 0.08 m from equilibrium. The position of the mass can be expressed as x(t) = A*cos(ω*t), with A set to 0.16 m and the phase φ set to 0. To find the period, the user must solve for angular frequency ω using the position at t = 0.50 s and then use the relationship between ω and the period (T = 2π/ω).

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  • Understanding of harmonic motion principles
  • Familiarity with trigonometric functions and their applications in physics
  • Knowledge of angular frequency and its relationship to oscillation period
  • Basic skills in algebra for solving equations
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  • Calculate angular frequency (ω) using the equation x(t) = A*cos(ω*t)
  • Determine the period of oscillation using the formula T = 2π/ω
  • Explore the effects of varying mass and spring constant on oscillation period
  • Study the concept of damping in oscillatory systems and its impact on period
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A mass which is resting on a horizontal frictionless surface is connected to a fixed spring. The mass is displaced 0.16 m from its equilibrium position and released. At t = 0.50 s, the mass is 0.08 m from its equilibrium position (and has not passed through it yet).

What is the period of oscillation of the mass?

I know I am suppose to put what I have done so far but I have given up with the trying. Could somebody please give me some guidance and explain please.

Thank you!
 
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You can generally write the position of the mass wrt to equilibrium as x(t)=A*cos(omega*t+phi), where A is the maximum displacement and phi is the phase. Since you know you have maximum displacement at t=0 you can set phi=0 and A=0.16m. So x(t)=(0.16m)*cos(omega*t). Enough hints, now can you put the values at t=0.5 sec in and solve for omega? Knowing omega, can you figure out the period?
 

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