Help : Perpendicular distance of the plane

  • Thread starter ahgang
  • Start date
  • #1
2
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Homework Statement


Find the perpendicular distance of the plane 5x+2y-z=-22 from the origin O by first finding the co-ordinates of the point P on the plane such that OP is perpendicular to the given plane.


Homework Equations


It only given plane vector,how i going to figure out the perpendicular distance?



The Attempt at a Solution


I really dont know where to start.Can help to elaborate?

Thanks
 

Answers and Replies

  • #2
798
1
Set x and y equal to zero, solve for z. The perpendicular distance will be the absolute value of this number.
 
  • #3
2
0
Set x and y equal to zero, solve for z. The perpendicular distance will be the absolute value of this number.

You mean (X,Y.Z) = (0.0.Z)?Then minus the plane location?
 
  • #4
hotvette
Homework Helper
996
5
One option is to use Lagrange Multipliers to get the coordinates of the point by treating it as a minimization problem (i.e. distance from origin to an arbitrary point) with the constraint that the arbitrary point must lie on the plane. Hint: minimizing the square of the distance also minimizes the distance.
 
Last edited:
  • #5
gneill
Mentor
20,913
2,862
You should be able to write a normal to the plane by inspection of the defining equation. Any line that is perpendicular to the plane must be parallel to this normal. So write a parametric equation of a line that passes through the origin that lies along this normal vector. Where does this line intersect the plane?
 

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