Help please, motion of charged particle in mag field

AI Thread Summary
To determine the time it takes for a proton to complete one orbit in a magnetic field of 0.758T, the relevant formula is r = mv/qB, where m is the mass of the proton, q is its charge, and B is the magnetic field strength. The relationship between the radius (r), velocity (v), and period (T) is established through the equation T = 2πr/v. After calculating the radius using the given values, the constant tangential speed can be used to find the period. The discussion concludes with the participant successfully finding the correct answer.
ballahboy
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A proton moves in a circular orbit perpendicular to a uniform magnetic field of 0.758T. Find the time it takes the proton to make one pass around the orbit.

Just need someone to help me start off. All I have is that the B=0.758T, q=1.6x10^-19C and m=1.67x10^-27kg. What formulas do I need to use to find t?
Thanks
 
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U can prove (i advice u to do it) that

r=\frac{mv}{qB}

Exploit the connection beteen T,v & r.

Daniel.
 
hmm so r=mv/qB is derived from mv^2/r=qvB. I got r=(1.4x10^-8)v. the thing is.. i don't kno the relationship between the time, radius and velocity. Do i use r to find the circumference and multiply that by the velocity? I am not really sure..
thanks for the response
 
Yes,that "v" is the constant tangential speed.Multiplied with the period should give exactly 2\pi r...

Daniel.
 
ok i got the correct answer now.. THanks a lot! :D
 
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