[HELP]problem in Second equation of Equilibrium

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The discussion revolves around a physics problem involving the equilibrium of a car's weight distribution across its wheels. The car weighs 2400 lbs, with its axles 7 ft apart and the center of gravity located 3 ft behind the axle. Participants are unsure about the correct equations to use for calculating the weight supported by each wheel, with some classmates suggesting answers of 686 lbs and 514 lbs. The original poster seeks clarification on the appropriate torque legends and how to approach the problem. Assistance is requested to solve the problem for an upcoming take-home quiz.
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[HELP]problem in Second Condition of Equilibrium

1. Homework Statement :

The axles of a 2400 lb car are 7 ft apart. if the centr of gravity of the car is 3 ft behind the axle, how much weight is supported by each of the car's wheels? II
2. Homework Equations

I'm not sure. i scanned my notes, then i found this equation
TF1+TF2=0
3. The Attempt at a Solution

i don't also have any idea about this. but my classmates told me that the answers are 686lb and 514lb

i can't solve for this because i don't know what the appropriate legends for them. whether Torque 1? or whatsoever. :|
 
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i need your help until this day because this is our take home quiz. thanks to those who will solve the problem for me. :)
 
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