Help Solve Hydraulic Problem Involving Spring and Rock

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A hydraulic problem involves a spring with a spring constant of 1456 N/m and a rock weighing 39.4 kg on an output plunger. The areas of the output and input plungers are 65 cm² and 15 cm², respectively. The discussion highlights the use of the hydraulic equation F1/A1 = F2/A2 to relate the forces and areas, along with the spring force equation F = kx. Participants provided guidance on how to approach the problem, leading to a clearer understanding of the calculations needed. The assistance was well-received, indicating a successful resolution to the inquiry.
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hydraulic problem, need help!

a hydraulic chamber in which a spring (spring constant = 1456 N/m) is attached to the input piston, and a rock of mass 39.4 kg rests on the output plunger. The piston and plunger are at the same height, and each has a negligible mass. By how much is the spring compressed from its unstrained position?

output plunger=65cm^2
input plunger=15cm^2

i have no clue how to get it started, can anyone help!
 
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Well you have the equation:
\frac{F_{1}}{A_{1}} = \frac{F_{2}}{A_{2}}

The output plunger has an Area of 65cm^2 and a force downward of the rock (Mass*Gravitational Accelertaion = Force)

And you know the area of the input plunger.

Also, the force on the spring is F=kx

Solve using that information. Good luck.
 
thanks

thank you so much that really helped a whole lot.

-foggy :smile:
 
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