Help: Solve Kinetic Energy of Pushing Piano up an Incline

AI Thread Summary
A mover is pushing a 328.4 kg piano up a 9.1-degree incline with a force of 722.1 Newtons over a distance of 7.4 meters. The initial calculations for kinetic energy yielded 5278.85 joules, but the expected answer is 1574.97 joules. Participants discuss the forces involved, including gravity and the net force acting on the piano, leading to differing results in kinetic energy calculations. Despite using similar methods, discrepancies in the final answers arise, with one user attributing the difference to rounding errors. The conversation emphasizes the importance of accurately accounting for all forces and potential calculation mistakes in physics problems.
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A mover is pushing a piano whose mass is 328.4 kg up a plane that is inclined 9.1 degrees to the horzontal. The force of 722.1 Newtons is applied parallel to the incline, whose length is 7.4 meters. Assuming that all contacts are smooth, find the kinetic energy of the piano at the end (in Joules).

F=ma
722.1cos9.1 x + 722.1sin9.1 y = 328.4a x
a = 2.17

vsquared = initial vsquared +2ax
v = 5.67 m/s

K=(1/2)mvsquared
K= 5278.85 joules

but the correct answer is 1574.97 joules. Can someone please tell me what I did wrong?
 
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Try to draw a free body diagram. In one direction, you have 722.1 Newtons acting on the piano. In the opposing direction, you have the force of gravity.

F = ma

Mover's force - force of gravity (sin 9.1 * mg) = Net Force

Acceleration = Net Force/Mass

...with this acceleration, just use the same method you had above to find Kinetic Energy.
 
thermodynamicaldude, I tried your method, but I got 1573.07 joules. The answer is 1574.97 joules.

722.1 - 509.52 = 212.58
212.58/328.4 = 0.647
v = 9.5756
k = 1573.07
 
The process seems right. The error may just be because of rounding.
 
no, it can't be because of rounding because I calculated it straight through without rounding.
 
So did I, but I got a slightly different answer. Which wasn't the same as yours or what it should be.
 
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