buffgilville
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A mover is pushing a piano whose mass is 328.4 kg up a plane that is inclined 9.1 degrees to the horzontal. The force of 722.1 Newtons is applied parallel to the incline, whose length is 7.4 meters. Assuming that all contacts are smooth, find the kinetic energy of the piano at the end (in Joules).
F=ma
722.1cos9.1 x + 722.1sin9.1 y = 328.4a x
a = 2.17
vsquared = initial vsquared +2ax
v = 5.67 m/s
K=(1/2)mvsquared
K= 5278.85 joules
but the correct answer is 1574.97 joules. Can someone please tell me what I did wrong?
F=ma
722.1cos9.1 x + 722.1sin9.1 y = 328.4a x
a = 2.17
vsquared = initial vsquared +2ax
v = 5.67 m/s
K=(1/2)mvsquared
K= 5278.85 joules
but the correct answer is 1574.97 joules. Can someone please tell me what I did wrong?