An object is given an initial velocity of 3.0 m/s up a 20 degree incline. Mass= 22.3 kg and coefficient of kinetic friction is .93.
W = (1/2)mv1^2-1/2mv0^2
W = Fdcos(u)
The Attempt at a Solution
So I added the forces together, mgsin(20) + .93mgcos(20)
and this times cos(20) should be the total work, right?
so then since the change in kinetic energy equals work i set -(1/2)mv^2= -Fdcos(20)
plugging in the mass for m, initial velocity for v, the forces due to friction and gravity for F, and solving for d, i got the wrong answer. where'd i go wrong? I also tried this taking out the cos(20) in the second work equation and still got it wrong.
Thanks, this is my first time using physics forums and i really hope i can get to understand this stuff...