Help solving log (natural number) equation

  • Thread starter Thread starter Muskox
  • Start date Start date
  • Tags Tags
    Log
AI Thread Summary
To solve the equation 2lnX = 2 + ln(X-1), the first step involves raising both sides by e to eliminate the logarithm. This leads to the equation X^2/(X-1) = e^2. By rearranging, it simplifies to X^2 = e^2(X-1), resulting in the quadratic equation X^2 - e^2X + e^2 = 0. The next steps involve applying the quadratic formula to find the values of X. This method provides a clear path to the solution of the logarithmic equation.
Muskox
Messages
2
Reaction score
0
I am stuck on finding the solution to this problem.

2lnX = 2 + ln(X-1)

Please show all steps for the solution.

Thank you.
 
Physics news on Phys.org
Try raising both sides by e. Use algebra to simplify.

- Warren
 
I get this far.
X^2/X-1 = e^2
X^2 = e^2(X-1)
x^2 = e^2 X - e^2
 
You now have a quadraic equation in x. Remember e2 is just a number.
 
I picked up this problem from the Schaum's series book titled "College Mathematics" by Ayres/Schmidt. It is a solved problem in the book. But what surprised me was that the solution to this problem was given in one line without any explanation. I could, therefore, not understand how the given one-line solution was reached. The one-line solution in the book says: The equation is ##x \cos{\omega} +y \sin{\omega} - 5 = 0##, ##\omega## being the parameter. From my side, the only thing I could...
Back
Top