Engineering Help solving this (simple?) circuit

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The discussion revolves around calculating voltage in a circuit with a 500-ohm and a 1k-ohm resistor in parallel, which is believed to yield an equivalent resistance of 333.3k ohms when combined with a 2k-ohm resistor in series. The user is applying Ohm's Law to determine the voltage across the indicated terminals, questioning the configuration and calculations. A response confirms the approach but suggests double-checking the calculation, as 333.3k ohms seems excessively high. The conversation emphasizes the importance of understanding series and parallel resistor configurations for accurate voltage measurement.
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i attached a picture of a circuit and my question is what is the voltage reading for the the indicated terminals... what I am thinking is that 500 and 2k ohm resistor in series... and then combine that in parallel with the 1k resistor? then use ohms law?
 

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What can you say about 500 and 1K resistors?
 
voltage is the same in parallel while current is the same in series. (ie: when you use a meter to measure voltage you put it across your resistor, hence you're measuring in parallel. If you want to measure current you put your meter leads and make it part of the circuit)
 
so the 500 and 1k resistors are in parallel i believe? which would give me a 333.3k resistor right? then that equiv resistor is pretty much in series with the 2 k resistor... which would mean the 1mA current is also flowing through the 333.3K resistor, then i could just use ohm's law to get voltage. please let me know if this is right
 
bjersey said:
so the 500 and 1k resistors are in parallel i believe? which would give me a 333.3k resistor right? then that equiv resistor is pretty much in series with the 2 k resistor... which would mean the 1mA current is also flowing through the 333.3K resistor, then i could just use ohm's law to get voltage. please let me know if this is right

That's correct.

See if you can double check your calculation, 333.3k sounds too large?
 

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