Help understanding Truss answer

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SUMMARY

The discussion focuses on calculating the force in member 2 of a truss structure suspended by two pin joints, with a specified applied force of 1 N. The method of sections is employed to analyze the forces, particularly in the y-direction. The correct interpretation of angles and the sign convention for forces is clarified, emphasizing that compressive forces are designated as negative while tension forces are positive. The final answer for the force in member 2 is confirmed to be 1 N.

PREREQUISITES
  • Understanding of truss analysis and the method of sections
  • Knowledge of static equilibrium principles, specifically the sum of forces
  • Familiarity with trigonometric functions and angle measurements
  • Basic concepts of tension and compression in structural members
NEXT STEPS
  • Study the method of sections in truss analysis
  • Learn about static equilibrium and the sum of forces in two dimensions
  • Explore trigonometric relationships in right triangles, particularly the 3-4-5 triangle
  • Review sign conventions for forces in structural engineering
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Students and professionals in civil engineering, structural engineering, and mechanics who are involved in truss analysis and force calculations.

NoobeAtPhysics
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Homework Statement



The truss is suspended by two pin joints. Each segment is 3 m wide and 4 m high. The applied force is F = 1 N. What is the force in member 2?

joints2.63.gif


Homework Equations



Sum of force = 0

The Attempt at a Solution



Using method of sections (to get force at 3), so taking the right portion

I am trying to understand the sum of the force in the y direction of the section.

sum of force y of portion =0 =-1 - J_3 cos(180-arctan(3/4))

My question, do we use 180-angle when looking at the angle,

also is it negative J_3, since the J_3 is pointing downwards?


I already know that the answer is 1N, I just don't understand this part.


Thank you.
 
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Any ideas?
 
I think you are looking for force in 3 by cutting right hand section thru 12,3, and 9? Forget about signs plus or minus from trig. You know that F acts down, so the vert force in 3 must act up, pushing in towards the member. Pushing forces are compression forces, usually designate as negative. Tension forces are positive. Use the properties of a 3-4-5 right triangle to get the compressive force in member 3.
 

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