Help with 45° Physics Homework Problem: Kate's Dilemma

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SUMMARY

The discussion focuses on a physics problem involving a 10 kg lawn spreader that Joe needs to accelerate at 1.39 m/s² over 1.5 seconds while applying force at a 45-degree angle. The correct calculation for the force required is F = (10 kg)(1.39 m/s²), resulting in 13.9 N. The angle of 45 degrees is crucial as it indicates that the force must be resolved into its horizontal and vertical components, impacting the overall force applied.

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Kate
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Hi, I'm new to this forum, I'm taking honors Physics this year and I'm not sure of what I'm doing in this homework problem...

"Joe pushes on the handle of a 10 kg lawn spreader. The handle makes a 45 degree angle with the horizontal. Joe wishes to accelerate the spreader from rest to 1.39 m/s/s in 1.5 seconds. What force must Joe apply to the handle? Neglect friction."

I've done part of it but I'm not sure whether its right...
F= (10 kg)(1.39 m/s/s)
F= 13.9 N
But where does the 45 degrees come in? Am I completely off track?

Thank you,
Kate
 
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hmm... meter / sec^2 are units of acceleration not velocity.
Remember that the force is applied at an angle, thus
having two abvious parts you can divide it into, advisably
in accordance with the direction of motion. :wink:
 
Thanks

Ohh I see. I didn't realize it was that easy haha. Thanks a lot
Kate
 

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