Help with 45° Physics Homework Problem: Kate's Dilemma

AI Thread Summary
To solve the problem of Joe pushing a 10 kg lawn spreader at a 45-degree angle, it's essential to consider both the acceleration and the angle of force application. The initial calculation of force, F = (10 kg)(1.39 m/s²), gives 13.9 N, but the angle means the force must be resolved into components. The vertical and horizontal components of the force need to be calculated to find the effective force applied in the direction of motion. Understanding that acceleration is expressed in meters per second squared, not velocity, is crucial for solving the problem correctly. This clarification helped the user realize the importance of the angle in their calculations.
Kate
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Hi, I'm new to this forum, I'm taking honors Physics this year and I'm not sure of what I'm doing in this homework problem...

"Joe pushes on the handle of a 10 kg lawn spreader. The handle makes a 45 degree angle with the horizontal. Joe wishes to accelerate the spreader from rest to 1.39 m/s/s in 1.5 seconds. What force must Joe apply to the handle? Neglect friction."

I've done part of it but I'm not sure whether its right...
F= (10 kg)(1.39 m/s/s)
F= 13.9 N
But where does the 45 degrees come in? Am I completely off track?

Thank you,
Kate
 
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hmm... meter / sec^2 are units of acceleration not velocity.
Remember that the force is applied at an angle, thus
having two abvious parts you can divide it into, advisably
in accordance with the direction of motion. :wink:
 
Thanks

Ohh I see. I didn't realize it was that easy haha. Thanks a lot
Kate
 
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