kathrynag
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Homework Statement
Prove or disprove:
(A-B)'=B'-A'
Homework Equations
The Attempt at a Solution
Let x\in(A-B)'
Then x\notin(A-B)
I'm not sure where to go from here...
VeeEight said:A-B is the set of elements in A that are not in B
So x is not in A-B means that x is in A but is not in B
You may want to try to think of some counterexamples before trying to show inclusion both ways.
VeeEight said:If you are working in R, then the complement of the set A-B would be R - {1, 2, 5}
You might want to try some simpler examples like A= (0,1) or {1, 2, 3} and B = [0,1] or {3, 4}
kathrynag said:A={1,2,3}
B={3,4}
universe ={1,2,3,4,5,6,7}
A-B={1,2}
(A-B)'={3,4,5,6,7}
So, if x is not an element of A-B, then x is not an element of {1,2}VeeEight said:Okay.
Ok, sokathrynag said:Homework Statement
Prove or disprove:
(A-B)'=B'-A'
Homework Equations
The Attempt at a Solution
Let x\in(A-B)'
Then x\notin(A-B)
I'm not sure where to go from here...
kathrynag said:A={1,2,3}
B={3,4}
universe ={1,2,3,4,5,6,7}
A-B={1,2}
(A-B)'={3,4,5,6,7}
x\in{3,4,5,6,7}kathrynag said:So, if x is not an element of A-B, then x is not an element of {1,2}
kathrynag said:A = {1,2,3} , B = {3,4} , universe = {1,2,3,4,5,6,7}
A-B = {1,2}
(A-B)' = {3,4,5,6,7}
kathrynag said:a={1,2,3}
b={3,4}
universe ={1,2,3,4,5,6,7}
a-b={1,2}
(a-b)'={3,4,5,6,7}
pizzasky said:keep going! What are a' , b' and b'-a' ?