Engineering Help with a circuit problem (Zener Diode)

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AI Thread Summary
The discussion focuses on analyzing a circuit with a zener diode and determining the current for various input voltages (Vs). Participants clarify the correct formula for calculating current, emphasizing that the voltage drop across the zener diode (Vd) must be considered based on the direction of current flow. It is highlighted that the zener diode does not conduct if the input voltage is between the zener voltage (Vz) and the forward voltage (Von). The importance of correctly applying the golden rule regarding current flow through the zener diode is reiterated, particularly for positive and negative input voltages. Overall, the conversation aims to ensure understanding of the zener diode's behavior in the circuit.
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Homework Statement



In the circuit below, a zener diode (VON = 0.7V, VZ = -5.7 V) is in series with two
resistors. Determine the current (I) if Vs is:

a) 6V b) 4V c) 0.2V d) – 0.2V e) – 4V f) – 6V

[PLAIN]http://img809.imageshack.us/img809/6995/zenerdiodecircuit.png

Homework Equations



I was thinking that I=V-Von/Req

The Attempt at a Solution


not sure if i have the correct formula.I'm not asking for the answer i Just want to know whether I'm using the correct formula. I was wondering what exactly is Vz
 
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You almost have the right formula, although I think you left out a parenthesis, and it's actually I = (Vs - Vd)/Req where Vd is the drop across the zener.

Vd = Von, I > 0
Vd = -Vz, I < 0

Note - the Zener is NOT as source of emf!
 
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So, when you say that:

Vd = Von, I > 0
Vd = -Vz, I < 0

Do you measure the current excluding the diode first?

Problem 1.c)
The voltage is 0.2V so would the current be measured excluding the diode to determine whether the current is negative and then, after figuring out the current, would you use that value to determine the value of Vd?

I=V/Req
I=0.2V/10ohm
I=0.02 Amps
Vd = Von, I > 0
then,
I=Vs-Vd/Req
I=0.2V-0.7V/10ohm
I=-0.05
 


november1992 said:
So, when you say that:

Vd = Von, I > 0
Vd = -Vz, I < 0

Do you measure the current excluding the diode first?

Problem 1.c)
The voltage is 0.2V so would the current be measured excluding the diode to determine whether the current is negative and then, after figuring out the current, would you use that value to determine the value of Vd?

I=V/Req
I=0.2V/10ohm
I=0.02 Amps
Vd = Von, I > 0
then,
I=Vs-Vd/Req
I=0.2V-0.7V/10ohm
I=-0.05

No. The zener conducts no current if Vz < Vs < Von. This is your golden rule. Remember that Vz is negative. No zener current means I = 0.

So when Vs > 0 you need Vs > Von to get any current. What you do is subtract Von from Vs and then compute the current. If it computes < 0 there is no current.

Likewise for Vs < 0. Subtract Vz from Vs. Remeber now Vs < 0. If current computes > 0 there is no current.
 
So I have to subtract the Von from the Vs?

So for a voltage of 6V, would the current be 0 since 0.7V-6V/10ohms=-0.53Amps
 
You contradicted yourself in those two sentences. Think about it. (Hint: the first one is correct).
 


rude man said:
No. The zener conducts no current if Vz < Vs < Von. This is your golden rule. Remember that Vz is negative. No zener current means I = 0.

So when Vs > 0 you need Vs > Von to get any current. What you do is subtract Von from Vs and then compute the current. If it computes < 0 there is no current.

Likewise for Vs < 0. Subtract Vz from Vs. Remeber now Vs < 0. If current computes > 0 there is no current.

So does this mean that if the voltage is 0.2V that I=0Amps because Vs<Von,
and if the voltage is -0.2V I=-0.09 Amps because [(-5.7V)-(-0.2V)]/10=0.09A?
 
Yes to the first part, no to the second.
To repeat: "Likewise for Vs < 0. Subtract Vz from Vs. Remeber now Vs < 0. If current computes > 0 there is no current. "

What is Vs - Vz? answer: -0.2 - (-5.7) = + 5.5V. Current computes to +5.5V/R > 0 so no current.

Again you wrote Vz - Vs when I said to compute Vs - Vz. Tsk tsk! :-)
 

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