Help with a probability question

  • Thread starter Thread starter justinbaker
  • Start date Start date
  • Tags Tags
    Probability
AI Thread Summary
The discussion revolves around a probability question related to the composition of Earth's atmosphere, specifically the nitrogen to oxygen ratio at 10 km altitude. The original poster expressed confusion about how to approach the problem, which involves understanding the number density of oxygen molecules as a function of height. A participant suggested that the solution involves using statistical mechanics principles, particularly the relationship between particle energy and probability distribution at different altitudes. The thread concludes with the original poster confirming they solved the problem but did not provide further details. Overall, the conversation highlights the application of statistical mechanics to atmospheric science.
justinbaker
Messages
34
Reaction score
0
solved

thanks for the help, i just solved it and did not have time to update the thread.



Please help me, i don't even know where to begin.

"Earths atmosphere is made up of a ratio of nitrogen to oxygen. The ratio is 78:21. Assumming constant temp, what is the ratio at 10km. Explain why your result is qualitatively reasonable. (Hint: this problem concerns the number density of oxygen molecules as a function of height. The denisty is related in a simple way to the probability that a given oxygen molecule will be found at a particular height.)
 
Last edited:
Physics news on Phys.org
justinbaker said:
Please help me, i don't even know where to begin.

"Earths atmosphere is made up of a ratio of nitrogen to oxygen. The ratio is 78:21. Assumming constant temp, what is the ratio at 10km. Explain why your result is qualitatively reasonable. (Hint: this problem concerns the number density of oxygen molecules as a function of height. The denisty is related in a simple way to the probability that a given oxygen molecule will be found at a particular height.)

Is it part of a stat mech class?
If it is, then I would guess they have in mind you using the fact that the probability of finding a particle with energy E is proportional to e^{-E/kT}. In this example, the energy is simply mgy (the kinetic energy will drop out..see below). Then the ratio of density at different altitude will simply be the ratio of the exponentials evaluated at those altitudes (since the temperature is taken to be constant, the kinetic energy will be the same and will drop out in the ratios). Because of the presence of m in the equation, the probability distributions with altitude will be different for the different molecules.
That's my guess...

Pat
 
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top