Solve Bobsled Problem: Find How Far Does It Travel Up a 30 Degree Incline

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The problem involves a bobsled traveling up a 30-degree incline with a kinetic friction coefficient of 0.60, starting at a speed of 25.0 m/s. To determine how far the sled travels before stopping, the mass can be assumed to be any value, as it cancels out in the calculations. The approach involves using energy equations, specifically the kinetic energy and the work done against friction and gravity. The calculation led to a distance of 88.28 meters, which needs verification against the forces acting on the sled. The discussion highlights the importance of correctly applying physics principles to solve for distance on an incline.
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Homework Statement


After a bobsled race, the sled and riders have been partially slowed down up in an icy incline, but they need to be brought to a stop. This happens on a portion of track inclined at 30 degrees that has a coefficient of kinetic friction of 0.60. The sled enters the incline at 25.0 m/s. How far does it travel along the incline before stopping?


Homework Equations


Ff=UFn
Fn=mgcosO
f=ma

The Attempt at a Solution


I couldn't find a way of doing it, since the , mass isn't given, maybe I'm overlooking something?
 
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Take any mass you like, say 100 kg. It should cancel out in the end.
 
how would you set up the equation? and also I am sort of clueless on how to find how far the sled goes... sorry.
 
Last edited:
I got as far as finding the resultant force for the vectors, which i got was 2000N, but that's as far as i got.
 
I think I would be inclined to use energy rather than force.
 
ok so using the formula 1/2vi^2=FG(cos 30) d
and solving for D, in which i got 88.28, would that be correct?
 

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