Help with a VT Graph: Acceleration & Deceleration Explained

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Homework Help Overview

The discussion revolves around creating a velocity-time (VT) graph for a parachute jump, focusing on the phases of acceleration and deceleration during the jump. Participants are exploring the dynamics of the jump and the implications of the graph's features.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants describe the phases of the jump, noting periods of acceleration and constant velocity. Questions are raised about the behavior of the jumper upon parachute deployment and the final velocity upon reaching the ground.

Discussion Status

The discussion is ongoing, with participants seeking clarification on the graph's representation and the physical implications of the jump phases. Some guidance has been offered regarding the need for further explanation of the graph's intent.

Contextual Notes

There are no specific homework equations provided, and participants are questioning the assumptions related to the jumper's behavior during and after parachute deployment.

GCSEsoon
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I need to do a VT graph showing a parachute jump, I need an explanation about the graph too.

Homework Equations


None

My Attempt:
Fhsst_rectmot15.png


From point 0-2 the jump is accelerating largely at a constant uniform. From point 2-4 the acceleration remains at a constant velocity. From point 4-6 the gradient decreases at a constant speed until it reaches zero.

Thanks a lot,
GCSEsoon
 
Last edited:
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GCSEsoon said:
I need to do a VT graph showing a parachute jump, I need an explanation about the graph too.

Homework Equations


None

My Attempt:Thanks a lot,
GCSEsoon

What is it you are attempting to show with your graph. Perhaps a little more of an explanation of your thinking about your graph is in order?
 
From point 0-2 the jump is accelerating largely at a constant uniform. From point 2-4 the acceleration remains at a constant velocity. From point 4-6 the gradient decreases at a constant speed until it reaches zero.
 
GCSEsoon said:
From point 0-2 the jump is accelerating largely at a constant uniform. From point 2-4 the acceleration remains at a constant velocity. From point 4-6 the gradient decreases at a constant speed until it reaches zero.

What happens when the chute deploys? The diver stops at constant velocity or slows to a final velocity of descent?

At the ground, how fast will the jumper stop? 2 seconds to hit the ground and slow his impact?
 

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