Help with alternating series sum

Abyssnight
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Homework Statement



Given the following: 1 - e + e2/2! - e3/3! + e4/4! + ...
Find the sum of series

Homework Equations



The MacLaurin equation for ex

The Attempt at a Solution



Well I thought that it would look like \sum(-1)^n\frac{e^n}{n!}
Tried the Ration Test and got no where. So I'm just kind of stumped
 
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Consider the MacLaurin series for ex.

ex = 1 + x + x2/2! + x3/3! + x4/4! ...

Now, what do you think you need to put into x to get the alternate series in your question?
 
Wow, haha. I must have had a long night to for some reason miss the obvious. x = -e and it works. Thank you haha.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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