Help with continuity of functions

AI Thread Summary
To determine the continuity of the given functions, values for 'a' must be found that equate the function outputs at the specified points. For function (a), continuity at x = 3 requires setting ax^2 equal to x - 7. In function (b), continuity at x = π means sin(aπ) must equal 1. For function (c), continuity at x = 1 necessitates equating x^2 + a^2 with 9 - x. Understanding the definition of continuity is essential for solving these problems effectively.
Cacophony
Messages
41
Reaction score
0

Homework Statement



For each of the following functions, find a value of a, (if such a value exists), which makes the function continuous.

a) f(x) = {ax^2...x > 3
...{x - 7...x ≤ 3

b) f(x) = {sin(ax)...x < (pi)
...{1...x ≥ (pi)

c) f(x) = {x^2 + a^2...x > 1
...{9 - x....x ≤ 1

Does anyone know how to do these?
 
Physics news on Phys.org
Hi Cacophony! :smile:

for (a), the only difficulty is at x = 3 …

so put the two equations equal at x = 3 :wink:
 
Do you know the definition of "continuous"? That's a good place to start.
 
I picked up this problem from the Schaum's series book titled "College Mathematics" by Ayres/Schmidt. It is a solved problem in the book. But what surprised me was that the solution to this problem was given in one line without any explanation. I could, therefore, not understand how the given one-line solution was reached. The one-line solution in the book says: The equation is ##x \cos{\omega} +y \sin{\omega} - 5 = 0##, ##\omega## being the parameter. From my side, the only thing I could...
Essentially I just have this problem that I'm stuck on, on a sheet about complex numbers: Show that, for ##|r|<1,## $$1+r\cos(x)+r^2\cos(2x)+r^3\cos(3x)...=\frac{1-r\cos(x)}{1-2r\cos(x)+r^2}$$ My first thought was to express it as a geometric series, where the real part of the sum of the series would be the series you see above: $$1+re^{ix}+r^2e^{2ix}+r^3e^{3ix}...$$ The sum of this series is just: $$\frac{(re^{ix})^n-1}{re^{ix} - 1}$$ I'm having some trouble trying to figure out what to...

Similar threads

Back
Top