Help with contravarient vector transformation

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SUMMARY

The discussion focuses on the transformation of contravarient vector components, specifically for vector A = <2,1> at point P with coordinates u1 = 1 and u2 = 1. The correct transformation to new coordinates u-1 = sqrt((u1)^2 + (u2)^2) and u-2 = arctan(u2/u1) reveals that the first component should yield 3/2^(1/2) instead of the incorrectly calculated 2/2^(1/2). The key issue identified is the necessity of summation over terms for u1 and u2 during the transformation process, which affects the calculation of the first component.

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Homework Statement



Let A = <2,1> be a vector with contravarient components at a point P with coordinants u1 = 1 , u2=1. Find the components a-1,a-2 (-1 and -2 are upstairs) of this vector with respect to the coordinates u-1 = sqrt((u1)^2 + (u2)^2) and u-2 = arctan(u2/u1).

Homework Equations




V^m(y) = (dy^m/dx^n) * V (x)^n

The Attempt at a Solution



I got the second component to be -1/2 which is correct but for the first component i keep getting 2/2^(1/2) but the answer is 3/2^(1/2).

The derivative of u-1 wrt u1 is:

1/2 [ (u1)^2 + (u2)^2) ]^(-1/2) * (2*u1)

then when i plug in u1=1 and u2 = 1 you get 1/(2^(1/2)). Then i multiply that by the a1 component 2 and this is how i got my answer.

Can anyone see where i went wrong?
 
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Remember that there is an implied summation over terms for u1 and u2 so that I think you are missing a term for u-1 with respect to u2.
 
If i sum over the terms then multiply by 2 i get 4/(2^(1/2)).

but i get the 3/2^(1/2) if i multiply the first term by the 2 then sum then second term.
but i don't know why you would do it this way since it breaks the order of operations.

also i didnt do a summation when i did the second component and i got the right answer.

I know that there should be a summation, but I am just not sure where/ when it should occurs

Thanks
 

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