Bestfrog
Homework Statement
A simple pendulum in quiet is released from the horizontal (##\theta=0##) (##\theta=90## for the vertical). Will the pendulum cover in the smaller time the arch from ##\theta=0## to ##\theta=30## or from ##\theta=30## to ##\theta=90##?
The Attempt at a Solution
I would like to know one thing: by the conservation on law, the speed in function of ##\theta## is ##v=\sqrt{2glsin\theta}##. Then I found a solution that says: "taking the differential I get ##dv= \sqrt{2gl} \frac{cos\theta}{2 \sqrt{sin\theta}} d\theta##. How can this passage is possible? I don't understand what happen