Help with digital signals (discrete fourier transform)

AI Thread Summary
The discussion revolves around calculating the Discrete Fourier Transform (DFT) of a 1Hz cosine wave sampled at 4 times per second for 1 second. The participant expresses confusion about how to start the problem and seeks guidance. They confirm the sampled values for the cosine wave as x[0]=1, x[1]=0, x[2]=-1, x[3]=0, and x[4]=1, which is validated by others. The conversation emphasizes the importance of correctly applying the DFT formula to these values to obtain the final results. Clarifications about sine versus cosine waves are also addressed, ensuring the focus remains on the cosine wave for the DFT calculation.
danhamilton
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I've been working on this problem for around three hours, and I'm getting nowhere... I think it may be that I don't have even the most basic grasp of the material to even get a decent start on the problem, but hopefully someone here will be able to help me...

Homework Statement



Calculate the Discrete Fourier Transform (DFT) of a 1Hz cosine wave
sampled 4 times per second for 1 second.

Homework Equations



<br /> <br /> X(K) = \sum_{n=0}^{N-1} x(n)e^{-j*2*\pi*\frac{k*n}{n}}<br /> <br />

The Attempt at a Solution


Honestly, I'm stumped. I don't even know where to start. I'm not asking anyone to do the problem for me, but I'd be forever greatfull if someone could start me in the right direction.

Thanks,
Dan
 
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Okay, start with this factoid: a 1 Hz sine wave, sampled 4 times per second for 1 second should give you 5 values (assuming you know the value at 0):
x[0]=
x[1]=
x[2]=
x[3]=
x[4]=

Fill in these values. Now apply the formula you listed above to find the DFT (come on, it's only 5 values!)

X[0]=
X[1]=
X[2]=
X[3]=
X[4]=
 
So am I right in saying
x[0]=1
x[1]=0
x[2]=-1
x[3]=0
x[4]=1
for a cosine wave?
 
danhamilton said:
So am I right in saying
x[0]=1
x[1]=0
x[2]=-1
x[3]=0
x[4]=1
for a cosine wave?

Yes, that's correct. A sine wave starts at 0, however. I think the answers will differ by an imaginary number in the end (equivalent to a phase shift, if I recall correctly).
 
MATLABdude said:
Yes, that's correct. A sine wave starts at 0, however. I think the answers will differ by an imaginary number in the end (equivalent to a phase shift, if I recall correctly).

Why do you find the x[n] values for a sine wave when the question is asking about a cosine wave?
 
danhamilton said:
Why do you find the x[n] values for a sine wave when the question is asking about a cosine wave?

Huh. I could swear your original post asked for sine. In that case, carry on!
 
So I would plug those values into the forumula, and then add all of the outputs together?
 
danhamilton said:
So I would plug those values into the forumula, and then add all of the outputs together?

Yup. And now?

X[0]=
X[1]=
X[2]=
X[3]=
X[4]=
 
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