- #1

bndnchrs

- 29

- 0

[tex]\frac{dx}{x^2} = \frac{dy}{y^2} = \frac{dz}{xy(z^2 + 1)}[/tex]

We can use the first two and find that

[tex] \frac{1}{x} - \frac{1}{y} = c [/tex]

I need to use all three to find a second function which is constant here. I've tried using the compendo and dividendo rule and I can't seem to get anywhere... I'm hoping just for a slight hint because I want to solve it myself but I'm really stuck at this point.

Thanks!