Help with Forces: Calculate Horizontal Stopping Force

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To calculate the horizontal stopping force of an 830 kg car traveling at 27 m/s that stops in 61 m, the relevant formulas include F = m*a and the kinematic equation a = (v^2 - v_i^2) / (2 * Δx). The user seeks clarification on the work-energy principle, specifically W = ΔK, and how it applies to their problem. Additionally, they request assistance in determining the stopping distance of the same car on a 19.9° slope while traveling at 33.5 m/s, emphasizing the need for formulas related to normal and frictional forces. Understanding these concepts is crucial for solving both scenarios effectively.
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Help with forces!

I need help with this, I've been trying but I don't understand it. Can anyone help me? :frown: :confused:

A 830.0 kg car traveling on a level road at 27.0 m/s (60.5 mi/hr) can stop, locking its wheels, in a distance of 61.0 m (200.1 ft). Find the size of the horizontal force which the car applies on the road while stopping.

 
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try W = \Delta K
 
I don't know how is exactly that formula, but I find one, maybe it's the same.

F=m*a

a= (v^2-v_{i}^2)/(2* \Delta x)


Now I have other problem

Find the stopping distance of that same car when it is traveling up a 19.9° slope, and it locks its wheels while traveling at 33.5 m/s (75.0 mi/hr). Assume that \mu_k does not depend on the speed.
 
Last edited:
please help me, this is urgent...
Any formulas will be helpful
 
1. What's the normal force exerted on the ground upon the car?
2. How is the magnitude of frictional force related to the magnitude of the normal force?
 
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