Help with frame and reference problem

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SUMMARY

The discussion centers on calculating the speed of an airplane traveling due east at 100 m/s with respect to the air, which is moving at 35 m/s at an angle of 30° west of due north. The user attempted to resolve the problem using vector components but miscalculated the horizontal and vertical components of the airplane's speed. The correct approach involves vector addition, specifically using the equation V[p,g] = V[p,a] + V[a,g], where V[p,g] represents the speed of the plane with respect to the ground. The accurate calculation reveals that the speed of the plane with respect to the ground is approximately 97.34 m/s.

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You are on an airplane traveling due east at 100 m/s with respect to the air. The air is moving with a speed 35 m/s with respect to the ground at an angle of 30° west of due north.

What is the speed of the plane with respect to the ground?
__________

So here's what I am doing:
Drew the whole right triangle thing to bring down air into its horizontal and vertical components. Vertical turned out to be 17.5m/s and horizontal 30.31m/s.

Then I broke up the speed of the plane into its horizontal and vertical components, but I used the same angle of 30 to get horizontal speed of 86.6 and vertical speed of 50. I'm pretty sure this part is wrong.

So to get the speed of the plane wrt ground, the equation is: V[p,g]=V[p,a] + V[a,g]
so v[p,g]=86.6+30.31=116.91. That was the wrong answer. I tried subtracting-wrong answer. I even used 60 degrees instead of 30 for breaking up the plane into vertical and horizontal, but that didnt work out either. I have no idea what I am doing.
 
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is the answer about 97.34? I guess you just made the triangle wrong its a simple vector addition...
 
Last edited:
Thats incorrect. Can anyone else help me with this?
 

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