Help with Homework Assignment: Two Puzzling Questions

AI Thread Summary
The discussion revolves around two homework questions related to physics. For the first question, the acceleration is correctly calculated as 1 m/s², but there is uncertainty regarding the equations for speed and distance. The second question addresses why mountain roads feature switchbacks; it highlights that climbing steep hills requires more power, necessitating gentler slopes and longer routes with sharp turns. The concept of energy conservation is emphasized, explaining that longer distances allow for less force to achieve the same work. Understanding these principles is crucial for solving the assignment effectively.
tucky
Messages
30
Reaction score
0
I am having a problem with two questions for my homework assignment.

1st question:

A force of 1 N acts on a mass of 1kg for a time of 1 s. (A)What is the acceleration of the mass? (B)What speed does the mass reach? (C)How far does the mass move?

Here is my answer but I think it is wrong:
(A) acceleration=1N/1kg = or 1 meter per second per second
(B) acceleration=change in velocity/time...I am not sure if that is the right equation to use
(C) velocity=change in average position/elapsed time ?

Then the second question that baffled me was:
in terms of power, explain why roads going up mountains are full of switchbacks and hairpin turn?

Is it something to do with the rate at which energy changes from on form to another?

I am really confused! Please help.
 
Physics news on Phys.org
Originally posted by tucky

(A) acceleration=1N/1kg = or 1 meter per second per second

This one is good.


I am not sure if that is the right equation to use

Try. What do you have to lose?

Regarding the second question: it's much harder (you need more power) to climb a steeper hill so given a mountain you build roads with a reasonable angle. At that angle you would need a longer mountain so you must make those sharp turns to keep the road on the mountain.
 
Sonty is completely correct.

In regards to the road, remember that "energy is conserved". Go up a particular distance requires fixed amount of work (mg times height moved) but since work= force times distance, if you go a longer distance you can do the same work using less force.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top