Help with income raise problem, possible exponential problem?

AI Thread Summary
To calculate the income after ten years with a starting salary of $60,000 and a 7% annual increase, an exponential growth formula should be used. The correct formula is based on compound interest: final salary = initial salary * (1 + rate)^years. Therefore, the income in the tenth year can be calculated as $60,000 * (1 + 0.07)^9, reflecting the compounding effect of the salary increase. This approach clarifies that the salary grows exponentially rather than linearly. Understanding this concept is crucial for accurately projecting future earnings.
calcunoob
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Homework Statement



Hi,
This is probably an easy equation and I know this is the pre-cal section and this is for my engineering math class but I feel like people in a pre-cal forum should be able to help! I'm writing an essay for my engineering math class and I am trying to calculate the income I will be earning by my tenth year of working. If my starting salary is $60,000 and that salary increases at a rate of 7% per year for ten years, what would my income be in the tenth year? THE ANSWER IS NOT 60,000 * .07x + 60,000! That's not what I'm looking for because you don't only get 60,000 plus 7% of 60,000 every year, if that makes sense... I think this may be an exponential equation but I'm not sure. I feel like an idiot because I'm in calculus too but for whatever reason I can't figure this out >.< Thank you!

Homework Equations



It's NOT 60,000 + (60,000 * .07x), I believe the answer will be an exponential equation.

The Attempt at a Solution



60,000 + (60,000 * .07x) <--- Not the right equation. Haha
 
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Please help :( lol
 
calcunoob said:
Please help :( lol

OK. If you earn $60,000 in Year 1, what do you earn in Year 2? What do you earn in Year 3? Keep going.

RGV
 

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