Help with math Matrices problem

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Homework Statement


Find the reduced row echelon form of the following matrix:

<br /> \begin{array}{c}\ \\ \\ \end{array}\;\begin{vmatrix}\;-4 &amp; 0 &amp; 4\;\\\;2 &amp; -4 &amp; 1\\\;-4 &amp; 4 &amp; -2\end{vmatrix}<br />

The Attempt at a Solution


<br /> \begin{array}{c}\ \\ \\ \end{array}\;\begin{vmatrix}\;1 &amp; 0 &amp; 1\;\\\;0 &amp; 1 &amp; \frac{1}{4}\\\;0 &amp; 0 &amp; 1\end{vmatrix}<br />

I've tried it a few times and keep getting that answer. I've inputted that answer and it's wrong. Am I supposed to keep reducing the third row (even though those are constants?)
 
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Look at your last row. It says 0x+0y=1 (Assuming this is an augmented matrix)
 
I figured it out. I was supposed to make the 1 and 1/4 in the third row zero's as well.
 
Yes, what you showed was "row echelon" form. "Reduced row echelon reduces above the diagonal also. Actually, until you get down to a row all 0s you will have just the identity matrix.
 
I had assumed not to touch the last row because that is usually the row of constants. In this case it wasn't - I had just assumed it was. :cool:
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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