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riseofphoenix
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Is it acceleration?
I found this graph online:
Would the answer be acceleration?
Yes, but what's your reasoning?riseofphoenix said:Would the answer be acceleration?
Doc Al said:Yes, but what's your reasoning?
Doc Al said:Yes, but what's your reasoning?
Doc Al said:Yes, but what's your reasoning?
Good. Another way to look at it is in terms of Hooke's law. The restoring force--and thus the acceleration--is maximum when the displacement from equilibrium is maximum.riseofphoenix said:Based on the graph: when v = 0, the mass has no kinetic energy, KE = ½mv2. Therefore, all of its energy is in the form of elastic potential energy, PEelastic = ½kx2. When PEelastic is maximum, the restoring force within the spring is also maximized. This results in the mass' acceleration to be maximized as the spring acts to return the mass to its equilibrium position.
This is what you need. If the net torque is constant, what can you say about alpha?riseofphoenix said:What about this one...number 2:
τnet = Iα
Doc Al said:This is what you need. If the net torque is constant, what can you say about alpha?
I think we can safely assume that the moment of inertia of the object is constant.riseofphoenix said:With respect to I (moment of inertia) you mean?
Doc Al said:I think we can safely assume that the moment of inertia of the object is constant.
How did you determine that? Look back at that equation.riseofphoenix said:So angular acceleration will not be constant but will be changing.
Doc Al said:How did you determine that? Look back at that equation.
Well we can assume that the object doesn't change its moment of inertia (otherwise the problem is silly). The key conclusion is that alpha is constant (and non-zero). And what does that tell you?riseofphoenix said:Wait so you're saying if the net torque is constant, then BOTH I (moment of inertia) and alpha (angular acceleration) are constant.
Doc Al said:Conservation of angular momentum has nothing to do with this one.
Imagine if instead of torque, the problem said that there was a constant net force on the object. What would you conclude then?
Right.riseofphoenix said:F = ma... So a constant F means a constant acceleration a.
No, it means that if a = some non-zero value, then velocity is changing.Which means, if a = 0, then velocity is non-zero.
Good!So in this case, angular velocity would be changing when α (angular acceleration) is constant.
Doc Al said:Right.
No, it means that if a = some non-zero value, then velocity is changing.
Good!
Once again I must ask: What is your reasoning? (What does it mean to be a harmonic of some fundamental frequency?)riseofphoenix said:This may be a really obvious question but...
is it the highest frequency, 740 Hz?
Doc Al said:Once again I must ask: What is your reasoning? (What does it mean to be a harmonic of some fundamental frequency?)
Good!riseofphoenix said:So essentially, to find the highest harmonic (using the fundamental frequency of 160 Hz), all I have to do is divide each option by 160 to see if it gives me an integer.
540/160 = 3.375
740/160 = 4.625
640/160 = 4 Is this the answer?
440/160 = 2.75
Doc Al said:Good!
(Nit pick: You're not finding the highest harmonic, just a higher harmonic. The 640 Hz is the only harmonic in the bunch. In this case it's the 4th harmonic.)
An oscillating spring is a mechanical system consisting of a mass attached to a spring, which is then attached to a fixed point. When the mass is displaced from its equilibrium position, it will experience a force from the spring that will cause it to oscillate back and forth.
The spring constant is a measure of the stiffness of a spring. In oscillating springs, it represents the amount of force required to stretch or compress the spring by a certain distance. A higher spring constant means a stiffer spring, and vice versa.
The mass of an object attached to a spring affects the period of oscillation, which is the time it takes for the object to complete one full cycle of oscillation. A heavier mass will have a longer period of oscillation compared to a lighter mass on the same spring.
The equation for the period of oscillation is T = 2π√(m/k), where T is the period, m is the mass of the object, and k is the spring constant. This means that the period is directly proportional to the square root of the mass and inversely proportional to the square root of the spring constant.
The amplitude of oscillation in an oscillating spring can be changed by altering the initial displacement of the mass or by changing the spring constant. Increasing the initial displacement will result in a larger amplitude, while increasing the spring constant will result in a smaller amplitude.