- #1

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## Homework Statement

Find the equation of the line perpendicular to

## Homework Equations

−8y − 8 − 16x = 0 and passing through the point (18, 0).

## The Attempt at a Solution

-8y = 16x +8

y = =2x -1

-2(x-18) = y - 0

-2x +36 = 0

-2 x = -36

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- Thread starter rkell48
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- #1

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Find the equation of the line perpendicular to

−8y − 8 − 16x = 0 and passing through the point (18, 0).

-8y = 16x +8

y = =2x -1

-2(x-18) = y - 0

-2x +36 = 0

-2 x = -36

- #2

NascentOxygen

Staff Emeritus

Science Advisor

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From this, you can immediately identify the gradient of that line.

Next step, determine what the gradient would be of any line that is

You would have covered this in class; or at least, you'll be able to find it in your textbook: if a line has a gradient

- #3

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i don't understand how to do it

:/

- #4

SammyS

Staff Emeritus

Science Advisor

Homework Helper

Gold Member

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Why did y disappear?## Homework Statement

Find the equation of the line perpendicular to

## Homework Equations

−8y − 8 − 16x = 0 and passing through the point (18, 0).

## The Attempt at a Solution

-8y = 16x +8

y = =2x -1

-2(x-18) = y - 0

-2x +36 = 0

-2 x = -36

- #5

PeterO

Homework Helper

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## Homework Statement

Find the equation of the line perpendicular to

## Homework Equations

−8y − 8 − 16x = 0 and passing through the point (18, 0).

## The Attempt at a Solution

-8y = 16x +8

y = =2x -1

-2(x-18) = y - 0

-2x +36 = 0

-2 x = -36

You need to be familiar with the gradient relationship for perpendicular lines

Even before you can use that, perhaps you could find the equation of the line parallel to

−8y − 8 − 16x = 0 and passing through the point (18, 0).

so we can assess you ability to do problems of this type.

Parallel is often considered the simpler problem, with perpendicular just adding one extra twist.

- #6

HallsofIvy

Science Advisor

Homework Helper

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- #7

PeterO

Homework Helper

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I wanted to see OP solve the parallel line to see if he/she knew a line parallel to -8y - 8 - 18x = 0 would have the formula -8y + c - 18x = 0

If OP knew to solve parallel lines that way, then he/she could simply use the fact that a line perpendicular to -8y - 8 - 18x = 0 would have the formula -18y + c + 8x = 0

In each case the given point is substituted to evaluate c.

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