Help with Pressure Calculation at Point C

AI Thread Summary
Pressure at Point C can be calculated using Bernoulli's Theorem, provided that Points A, B, and C are in the same streamline. The initial pressure at Point A is 559 mbar, and the dimensions of the cylinders influence the flow characteristics. Changing the shape of the chamber from a cylinder to an oval does not invalidate the application of Bernoulli's Theorem, as long as the flow remains incompressible and irrotational. The discussion emphasizes the importance of understanding fluid dynamics principles for accurate pressure calculations. Mastery of these concepts is essential for selecting the appropriate umbrella valve for the system.
anthonynichola
Messages
4
Reaction score
0
Hello, is there anyone who can help me with this? I am completely stumped. Here is the situation:

Point A: Water is flowing into a valve at 559 (mbar) of pressure and into a cylinder that's 12 mm long and 7mm in diameter.

Point B: It then will enter another cylinder that is 40 mm long 10 mm in diameter.

Point C: At this point it will enter another cylinder 5mm long and 7mm in diameter.


Im trying to figure out what the pressure will be at Point C so that I can choose the correct umbrella valve to use so that water flows out of the chamber.
 
Physics news on Phys.org
anthonynichola said:
Hello, is there anyone who can help me with this? I am completely stumped. Here is the situation:

Many... :smile:

Point A: Water is flowing into a valve at 559 (mbar) of pressure and into a cylinder that's 12 mm long and 7mm in diameter.

Point B: It then will enter another cylinder that is 40 mm long 10 mm in diameter.

Point C: At this point it will enter another cylinder 5mm long and 7mm in diameter.


Im trying to figure out what the pressure will be at Point C so that I can choose the correct umbrella valve to use so that water flows out of the chamber.

If all the points : A,B and C lie in the same streamline, you can apply "Bernoulli's Theorem", at A,B and C respectively.

Best of luck buddy ! :)
 
Thanks! Does this apply also if I change the shape of the chamber? Meaning, instead of a cylinder its an oval? I am young and inexperienced lol
 
anthonynichola said:
Thanks! Does this apply also if I change the shape of the chamber? Meaning, instead of a cylinder its an oval?

Provided that when the shape of chamber is changed, that is A,B and C are ovals, then also you can apply Bernoulli's Theorem, if A,B and C lie in a same streamline.

I'm young and inexperienced lol

And So am I. :-p
 
If the flow is incrompressible and also irrotational then you can apply Bernulli's theorem between any points in the flow.
 
The rope is tied into the person (the load of 200 pounds) and the rope goes up from the person to a fixed pulley and back down to his hands. He hauls the rope to suspend himself in the air. What is the mechanical advantage of the system? The person will indeed only have to lift half of his body weight (roughly 100 pounds) because he now lessened the load by that same amount. This APPEARS to be a 2:1 because he can hold himself with half the force, but my question is: is that mechanical...
Some physics textbook writer told me that Newton's first law applies only on bodies that feel no interactions at all. He said that if a body is on rest or moves in constant velocity, there is no external force acting on it. But I have heard another form of the law that says the net force acting on a body must be zero. This means there is interactions involved after all. So which one is correct?
Thread 'Beam on an inclined plane'
Hello! I have a question regarding a beam on an inclined plane. I was considering a beam resting on two supports attached to an inclined plane. I was almost sure that the lower support must be more loaded. My imagination about this problem is shown in the picture below. Here is how I wrote the condition of equilibrium forces: $$ \begin{cases} F_{g\parallel}=F_{t1}+F_{t2}, \\ F_{g\perp}=F_{r1}+F_{r2} \end{cases}. $$ On the other hand...
Back
Top